Draw the enantiomer of the following monosaccharides, and in each pair identify the D sugar and the L sugar.
b.

Question

Draw the enantiomer of the following monosaccharides, and in each pair identify the D sugar and the L sugar.

b. Structural representation of a monosaccharide, showing its enantiomer with labeled D and L sugars.

Accepted Answer

Welcome back, everyone draw the enantiomer of the given sugar label the original sugar and its in Antium as D and L sugars. As the problem suggests, we want to draw the inan tumor of the given sugar. And we want to recall that in an tumors are non superimposable mirror images of each other. So we simply want to draw the mirror plane and we want to reflect our structure. So first of all, let's begin by adding co and now for every horizontal bond, we simply want to swap our substituents. If we had hydroxy on the left, now we will have hydroxy group on the right and hydrogen on the left. And we can clearly see how these two parts are reflected relative to the mirror, right. So now for the next chiral position, we want to draw a horizontal bond. And then if hygen was on the left, now we will observe hygen on the right and hydroxy group on the left. Similarly, for the next carbon, we will have hydroxy group on the left hygen on the right. For the final position, we're going to add hydrogen on the left and hydroxy group on the right, we finish with CTO H, this is not a carl carbon, right? And it is part of a vertical bond. So now we simply want to also understand that this is galactose, but we want to define it as D or L. So basically, what we have to do is identify the carl position that is farthest from Carbonel. If we start with Carbonel co, we have to go down and identify the final, the final chiral carbon atom, right. So let's identify those. And we want to understand if the hydroxy group is on the left or on the right. If hydroxy group is on the left at that specific chiral center, then we classify such an inaner as L if it's on the right, that would be ad in an tumor. As we can see, the original structure has hydroxy group at the final chiral carbon atom on the left side. And this means that the original structure represents L galactose. And now if we consider the, the in Antium, that would be the galactose because we have hydroxy group on the right side and that would be our final answer. So let's label them. And thank you for watching.

Draw the enantiomer of the following monosaccharides, and in each pair identify the D sugar and the L sugar.
b.

Verified video answer for a similar problem:

Key Concepts

Enantiomers

D and L Configuration

Fischer Projection

Draw the enantiomer of the following monosaccharides, and in each pair identify the D sugar and the L sugar.b.

Verified video answer for a similar problem:

Key Concepts

Enantiomers

D and L Configuration

Fischer Projection

Draw the enantiomer of the following monosaccharides, and in each pair identify the D sugar and the L sugar.
b.