Table of contents

1. The Chemical World9m
- The Scientific Method
  9m
2. Measurement and Problem Solving2h 19m
3. Matter and Energy2h 15m
4. Atoms and Elements2h 33m
5. Molecules and Compounds1h 50m
6. Chemical Composition1h 23m
7. Chemical Reactions1h 43m
8. Quantities in Chemical Reactions1h 8m
9. Electrons in Atoms and the Periodic Table2h 32m
10. Chemical Bonding2h 10m
11 Gases2h 7m
12. Liquids, Solids, and Intermolecular Forces1h 11m
13. Solutions3h 1m
14. Acids and Bases2h 14m
15. Chemical Equilibrium1h 27m
16. Oxidation and Reduction1h 33m
17. Radioactivity and Nuclear Chemistry53m

13. Solutions

Osmolarity

Introduction to Chemistry

13. Solutions

Osmolarity

Previous problemNext problem

Struggling with Introduction to Chemistry?

Join thousands of students who trust us to help them ace their exams!Watch the first video

Multiple Choice

How many milligrams of nitride ions are required to prepare 820 mL of 0.330 M Ba₃N₂ solution?

120 mg

320 mg

560 mg

760 mg

7600 mg

Previous problemNext problem

Verified step by step guidance

First, understand the problem: We need to find out how many milligrams of nitride ions are required to prepare a given volume of a barium nitride solution with a specific molarity.

Identify the chemical formula for barium nitride, which is \( \text{Ba}_3\text{N}_2 \). This indicates that each formula unit contains two nitride ions (\( \text{N}^{3-} \)).

Calculate the number of moles of \( \text{Ba}_3\text{N}_2 \) in the solution using the formula \( \text{Molarity} = \frac{\text{moles of solute}}{\text{liters of solution}} \). Convert 820 mL to liters by dividing by 1000.

Use the stoichiometry of the compound \( \text{Ba}_3\text{N}_2 \) to determine the moles of nitride ions. Since there are two nitride ions per formula unit, multiply the moles of \( \text{Ba}_3\text{N}_2 \) by 2.

Convert the moles of nitride ions to milligrams. First, find the molar mass of \( \text{N}^{3-} \) (which is approximately 14.01 g/mol), then convert grams to milligrams by multiplying by 1000.