Table of contents

1. The Chemical World9m
- The Scientific Method
  9m
2. Measurement and Problem Solving2h 19m
3. Matter and Energy2h 15m
4. Atoms and Elements2h 33m
5. Molecules and Compounds1h 50m
6. Chemical Composition1h 23m
7. Chemical Reactions1h 43m
8. Quantities in Chemical Reactions1h 8m
9. Electrons in Atoms and the Periodic Table2h 32m
10. Chemical Bonding2h 10m
11 Gases2h 7m
12. Liquids, Solids, and Intermolecular Forces1h 11m
13. Solutions3h 1m
14. Acids and Bases2h 14m
15. Chemical Equilibrium1h 27m
16. Oxidation and Reduction1h 33m
17. Radioactivity and Nuclear Chemistry53m

10. Chemical Bonding

Multiple Bonds

Introduction to Chemistry

10. Chemical Bonding

Multiple Bonds

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Multiple Choice

Identify the least stable covalent bond.

N–C

F–Na

N=C

N≡C

all same strength

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Verified step by step guidance

Understand that covalent bonds involve the sharing of electron pairs between atoms. The stability of a covalent bond is influenced by factors such as bond order, electronegativity differences, and atomic size.

Recognize that bond order refers to the number of shared electron pairs between two atoms. A higher bond order generally indicates a stronger and more stable bond.

Analyze the given options: N–C, F–Na, N=C, N≡C, and 'all same strength'. Note that F–Na is not a covalent bond; it is an ionic bond due to the large electronegativity difference between F and Na.

Compare the bond orders: N–C is a single bond (bond order of 1), N=C is a double bond (bond order of 2), and N≡C is a triple bond (bond order of 3). Higher bond orders typically mean stronger bonds.

Conclude that among the covalent bonds, the N–C single bond is the least stable due to its lower bond order compared to the double and triple bonds. Therefore, the least stable covalent bond is N–C.