If 53.2 g Al at 120.0 ºC is placed in 110.0 g H2O at 90 ºC within an insulated container that absorbs a negligible amount of heat, what is the final temperature of the aluminum? The specific heat capacities of water and aluminum are 4.184 J/g ∙ ºC and 0.897 J/g ∙ ºC, respectively.

Write the equation for heat transfer: \( q_{\text{lost by Al}} = q_{\text{gained by H2O}} \). This can be expressed as \( m_{\text{Al}} \cdot c_{\text{Al}} \cdot (T_{\text{final}} - T_{\text{initial, Al}}) = -m_{\text{H2O}} \cdot c_{\text{H2O}} \cdot (T_{\text{final}} - T_{\text{initial, H2O}}) \).