Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
How many grams of carbon dioxide, CO2, are present in a 0.150 L flask recorded at 525 mmHg and 32 ºC? a) 1.77 g b) 0.93 g c) 0.66 g d) 0.18 g e) 0.052 g
A
1.77 g
B
0.93 g
C
0.66 g
D
0.18 g
E
0.052 g
Verified step by step guidance
1
Convert the temperature from Celsius to Kelvin by adding 273.15 to the Celsius temperature: T(K) = 32 + 273.15.
Convert the pressure from mmHg to atm using the conversion factor: 1 atm = 760 mmHg. Calculate P(atm) = 525 mmHg / 760 mmHg.
Use the ideal gas law equation, PV = nRT, to solve for the number of moles (n) of CO2. Rearrange the equation to n = PV / RT, where R is the ideal gas constant (0.0821 L·atm/mol·K).
Substitute the values for P, V, and T into the equation to calculate the number of moles of CO2: n = (P(atm) * 0.150 L) / (0.0821 L·atm/mol·K * T(K)).
Convert the moles of CO2 to grams using the molar mass of CO2 (44.01 g/mol): mass (g) = n * 44.01 g/mol.