Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
Manganese (V) hydroxide has a measured solubility of 3.4×10–5 M at 25ºC. Calculate its Ksp value.
A
5.7×10–9
B
1.5×10–27
C
7.7×10–27
D
4.8×10–24
Verified step by step guidance
1
Identify the chemical formula for manganese (V) hydroxide, which is Mn(OH)₅.
Write the dissociation equation for Mn(OH)₅ in water: Mn(OH)₅(s) ⇌ Mn⁵⁺(aq) + 5OH⁻(aq).
Express the solubility product constant (Ksp) expression for the dissociation: Ksp = [Mn⁵⁺][OH⁻]⁵.
Use the given solubility of Mn(OH)₅, which is 3.4×10⁻⁵ M, to determine the concentrations of ions at equilibrium: [Mn⁵⁺] = 3.4×10⁻⁵ M and [OH⁻] = 5 × 3.4×10⁻⁵ M.
Substitute the ion concentrations into the Ksp expression and solve for Ksp: Ksp = (3.4×10⁻⁵) × (5 × 3.4×10⁻⁵)⁵.