How many moles of ATP are produced by phosphorylation in the following?
c. Catabolism of 1 mol of acetyl-CoA in the citric acid cycle

Question

How many moles of ATP are produced by phosphorylation in the following?

c. Catabolism of 1 mol of acetyl-CoA in the citric acid cycle

Accepted Answer

Hi, everybody. And welcome back. Our next question says, how many total moles of A TP at maximum are generated from the complete oxidation of five moles of acetyl coa through the citric acid cycle and subsequent oxidative phosphorylation. A 25 moles of A T PB, 35 moles of A TP C 60 moles of A TP or D 80 moles of A TP. So let's think this through first a little bit simplified. So we'll start by thinking about how much A TP is generated from one mole of a Cy coe. So that acetyl coa enters the citric acid cycle. And we're going to have one mole of A TP generated directly from that citric acid cycle. And then we're also going to have three moles of N A DH and one mole of fa DH two as products of that cycle. And both of these are going to bring electrons over to the electron transport chain. And that will be that process of oxidative phosphorylation that will phosphorylation, excuse me, that will result in the production of A TP. And that will be in the amount of for every one mole of N A DH that will produce 2 to 3 moles of a TP, depending on the exact conditions under which this is operating. And for every one mole of FA DH two, you will get 1 to 2 moles of ATP. And that's because the fa DH two comes to the electron transport chain just a little bit further along than N A DH. Now we have this variable yield but note that our question asks us for the maximum yield of A TP. So we'll use the larger number saying that for every mole of a DNA DH, we'll expect three moles of a TP, every mole of FA DH 22 moles of A TP. So let's calculate for each mole of acetyl coa how many moles of A TP will be generated after both of these processes. So again, one mole of acetyl coa will lead to one mole of a TP directly from the citric acid cycle plus three moles of N A DH. And that will be multiplied by three moles of a TP per mole of N A DH. Change that parenthesis made that a fraction there. So just make my parentheses a little bit larger. And then we will add two moles of a TP divided by or per each mole of FA DH two. And that's multiplied by one mole of FA DH two. So hang on one second, have to scoot that over since I didn't write in one mole of fa DH two in this equation here. So to add that up, we have our one mole of ATP and then we have three moles of N A DH multiplied by three moles of a TP per mole of N A DH. So that makes nine moles of a TP as a result of the at and then one mole of FA DH two multiplied by two moles of A TP per mole of FA DH two. So that will be two malls of a TP. And so that's going to equal one plus nine plus two, 12 moles of ATP generated for every one mole of a Cy Coe. So now we want to know how many total moles will be yielded if we oxidize five moles of a silo away. So multiplied by five multiply our 12 moles of ATP by five. And our answer is 60 moles of A TP. So our answer choice will be choice C that our maximum yield of A TP from completely oxidizing five moles of acetyl coa through the citric acid cycle through oxidated phosphorylation is choice C 60 moles of A TP. See you in the next video.

How many moles of ATP are produced by phosphorylation in the following?
c. Catabolism of 1 mol of acetyl-CoA in the citric acid cycle

Verified video answer for a similar problem:

Key Concepts

Citric Acid Cycle

ATP Production

Mole Concept

How many moles of ATP are produced by phosphorylation in the following?c. Catabolism of 1 mol of acetyl-CoA in the citric acid cycle

Verified video answer for a similar problem:

Key Concepts

Citric Acid Cycle

ATP Production

Mole Concept

How many moles of ATP are produced by phosphorylation in the following?
c. Catabolism of 1 mol of acetyl-CoA in the citric acid cycle