Complete the following equations. (Hint: Remember that a nitrogen with three groups bound to it has a lone pair and one with four does not)
a.

Question

Complete the following equations. (Hint: Remember that a nitrogen with three groups bound to it has a lone pair and one with four does not)

a. Chemical equation showing an amine reacting with hydrochloric acid, with a question mark indicating an incomplete reaction.

Accepted Answer

All right. Hi everyone. So this question is asking us to determine the product formed by completing the following reaction equation. Note, nitrogen bonded to three groups has a lone pair while nitrogen bonded to four groups does not. And here our reaction involves cyclops, amine and hydrogen bromide or simply HBR. So recall first and foremost that copy amine is a neutral amine and therefore a weak base. Whereas HBR by contrast is a strong asset. So all this is to say is that this reaction is an example of an acid base reaction involving a proton transfer. So let's recall some definitions according to the brony lai acid based definition, recall that bases are species that accept protons. Whereas acids on the other hand are species that donate the protons that the bases will therefore accept. So if the base in question happens to be an amine involving a nitrogen. The first thing that's worth mentioning here is that nitrogen encyclopedia a mean has a lo pair of electrons that was not previously drawn. This loan pair of electrons is important because it is what allows a means to accept protons and behave like bases. So when considering the product of this reaction, the base structure of cyclo pencil amine is not going to change significantly. The only difference here is that after the acid base reaction, nitrogen will gain a new bond between itself and the proton that it received. So in this case, instead of having an NH two in the product of my reaction, it would be NH three, right, because a proton has been gained now as a consequence of this nitrogen in the final product is going to have or bonds to other groups. This means that there is no longer a lone pair of electrons. Instead, there's going to be a positive charge on nitrogen resulting in the formation of an ammonium ion. So in this case, the addition of a proton increased the charge from neutral or zero to positive one. And so the opposite is going to happen to HBR which is our asset because H Pr specifically bromine is going to lose the only proton it has. So because a proton has been lost, the charge of bromine is going to decrease from zero to negative one. So in addition to having the ammonium ion, we're also going to see the formation of a bromide an ion. This means that our acid base reaction result in an ammonium salt because here the cyclops, ammonium ion has a positive charge on nitrogen and bromide is the counter ion that balances the charge on nitrogen and there you have it. So this reaction was an example of an acid base reaction between cyclops, amine and HBR. This resulted in a proton transfer that produced an ammonium salt. Specifically, we have cyclops ammonium bromide with a positive charge on nitrogen and a negative charge on bromide. And so with that being said, thank you so very much for watching. And I hope you found this helpful.

Complete the following equations. (Hint: Remember that a nitrogen with three groups bound to it has a lone pair and one with four does not)
a.

Verified video answer for a similar problem:

Key Concepts

Valence Shell Electron Pair Repulsion (VSEPR) Theory

Hybridization

Lone Pairs

Complete the following equations. (Hint: Remember that a nitrogen with three groups bound to it has a lone pair and one with four does not)a.

Verified video answer for a similar problem:

Key Concepts

Valence Shell Electron Pair Repulsion (VSEPR) Theory

Hybridization

Lone Pairs

Complete the following equations. (Hint: Remember that a nitrogen with three groups bound to it has a lone pair and one with four does not)
a.