A student formed a club at their school. They have 13 members, and need to elect a president, vice president, and treasurer. How many ways are there to fill these officer positions?
Table of contents
- 1. Introduction to Statistics53m
- 2. Describing Data with Tables and Graphs2h 1m
- 3. Describing Data Numerically1h 48m
- 4. Probability2h 26m
- 5. Binomial Distribution & Discrete Random Variables2h 55m
- 6. Normal Distribution & Continuous Random Variables1h 48m
- 7. Sampling Distributions & Confidence Intervals: Mean2h 8m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 20m
- 9. Hypothesis Testing for One Sample2h 23m
- 10. Hypothesis Testing for Two Samples3h 25m
- 11. Correlation1h 6m
- 12. Regression1h 4m
- 13. Chi-Square Tests & Goodness of Fit1h 30m
- 14. ANOVA1h 4m
4. Probability
Counting
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
How many ways are there to arrange the letters in the word CALCULUS?
A
40,320
B
5,040
C
720
D
6

1
Identify the total number of letters in the word 'CALCULUS'. There are 8 letters.
Determine if there are any repeated letters. In 'CALCULUS', the letter 'C' appears twice and the letter 'U' appears twice.
Use the formula for permutations of a multiset: \( \frac{n!}{n_1! \times n_2! \times \ldots \times n_k!} \), where \( n \) is the total number of items to arrange, and \( n_1, n_2, \ldots, n_k \) are the frequencies of the repeated items.
Substitute the values into the formula: \( \frac{8!}{2! \times 2!} \). Calculate \( 8! \) for the total arrangements and divide by the factorials of the repeated letters.
Simplify the expression to find the number of unique arrangements of the letters in 'CALCULUS'.
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