Evaluate the given expression.
Table of contents
- 1. Introduction to Statistics53m
- 2. Describing Data with Tables and Graphs2h 1m
- 3. Describing Data Numerically1h 48m
- 4. Probability2h 26m
- 5. Binomial Distribution & Discrete Random Variables2h 55m
- 6. Normal Distribution & Continuous Random Variables1h 48m
- 7. Sampling Distributions & Confidence Intervals: Mean2h 8m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 20m
- 9. Hypothesis Testing for One Sample2h 23m
- 10. Hypothesis Testing for Two Samples3h 25m
- 11. Correlation1h 6m
- 12. Regression1h 4m
- 13. Chi-Square Tests & Goodness of Fit1h 30m
- 14. ANOVA1h 4m
4. Probability
Counting
Struggling with Statistics for Business?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Evaluate the given expression. 11C7
A
330
B
120
C
5,040
D
7,920

1
Understand that the expression 11C7 represents a combination, which is used to determine the number of ways to choose 7 items from a set of 11 items without regard to order.
Recall the formula for combinations: \( nCk = \frac{n!}{k!(n-k)!} \), where \( n \) is the total number of items, \( k \) is the number of items to choose, and \( ! \) denotes factorial.
Substitute the values into the formula: \( 11C7 = \frac{11!}{7!(11-7)!} \). This simplifies to \( \frac{11!}{7!4!} \).
Calculate the factorials: \( 11! = 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \), \( 7! = 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \), and \( 4! = 4 \times 3 \times 2 \times 1 \).
Simplify the expression by canceling out common terms in the numerator and denominator, and compute the final value of \( 11C7 \).
Watch next
Master Introduction to Permutations with a bite sized video explanation from Patrick
Start learningRelated Videos
Related Practice
Multiple Choice