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Multiple Choice
Assume a population in Hardy-Weinberg equilibrium with these genotypic frequencies: AA = 0.25, Aa = 0.50, and aa = 0.25. If you remove all the homozygous dominants and allow the remaining population to reproduce (again under Hardy-Weinberg conditions), what will be the frequency of homozygous dominants in the next generation?
A
0
B
0.22
C
0.44
D
0.50
E
0.11
Verified step by step guidance
1
Start by understanding the Hardy-Weinberg principle, which states that allele and genotype frequencies in a population will remain constant from generation to generation in the absence of other evolutionary influences.
Given the initial genotypic frequencies: AA = 0.25, Aa = 0.50, and aa = 0.25, calculate the allele frequencies. The frequency of allele A (p) is calculated as: p = (2 * frequency of AA + frequency of Aa) / 2.
Similarly, calculate the frequency of allele a (q) using: q = (2 * frequency of aa + frequency of Aa) / 2. Since the population is in Hardy-Weinberg equilibrium, p + q should equal 1.
After removing all homozygous dominants (AA), recalculate the allele frequencies in the remaining population. The new frequency of allele A (p') is the frequency of A alleles from the heterozygotes only.
Using the new allele frequencies, apply the Hardy-Weinberg equation to find the expected genotypic frequencies in the next generation. The frequency of homozygous dominants (AA) in the next generation is given by p'^2.