Medical Malpractice In a study of 1228 randomly selected medical malpractice lawsuits, it was found that 856 of them were dropped or dismissed (based on data from the Physicians Insurers Association of America). Use the bootstrap method to construct a 95% confidence interval estimate of the proportion of lawsuits that are dropped or dismissed. Use 1000 bootstrap samples. How does the result compare to the confidence interval found in Exercise 16 “Medical Malpractice” from Section 7-1?
Table of contents
- 1. Intro to Stats and Collecting Data55m
- 2. Describing Data with Tables and Graphs1h 55m
- 3. Describing Data Numerically1h 45m
- 4. Probability2h 16m
- 5. Binomial Distribution & Discrete Random Variables2h 33m
- 6. Normal Distribution and Continuous Random Variables1h 38m
- 7. Sampling Distributions & Confidence Intervals: Mean1h 53m
- 8. Sampling Distributions & Confidence Intervals: Proportion1h 12m
- 9. Hypothesis Testing for One Sample2h 19m
- 10. Hypothesis Testing for Two Samples3h 22m
- 11. Correlation1h 6m
- 12. Regression1h 4m
- 13. Chi-Square Tests & Goodness of Fit1h 20m
- 14. ANOVA1h 0m
8. Sampling Distributions & Confidence Intervals: Proportion
Confidence Intervals for Population Proportion
Problem 7.3b
Textbook Question
Voting Survey In a survey of 1002 people, 70% said that they voted in a recent presidential election (based on data from ICR Research Group). Voting records show that 61% of eligible voters actually did vote.
b. Find a 95% confidence interval estimate of the percentage of people who say that they voted.

1
Step 1: Identify the sample proportion (p̂) and sample size (n). The sample proportion is the percentage of people who said they voted, which is 70% or 0.70. The sample size is 1002.
Step 2: Determine the critical value (z*) for a 95% confidence level. For a 95% confidence interval, the critical value z* is approximately 1.96 (this value corresponds to the standard normal distribution).
Step 3: Calculate the standard error (SE) of the sample proportion using the formula: SE = sqrt((p̂ * (1 - p̂)) / n). Substitute p̂ = 0.70 and n = 1002 into the formula.
Step 4: Compute the margin of error (ME) using the formula: ME = z* × SE. Use the critical value z* = 1.96 and the standard error calculated in Step 3.
Step 5: Construct the confidence interval by adding and subtracting the margin of error from the sample proportion. The confidence interval is given by: [p̂ - ME, p̂ + ME].

This video solution was recommended by our tutors as helpful for the problem above
Video duration:
4mPlay a video:
Was this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Confidence Interval
A confidence interval is a range of values, derived from sample statistics, that is likely to contain the true population parameter with a specified level of confidence, typically 95%. It provides an estimate of uncertainty around a sample statistic, allowing researchers to infer about the population from which the sample was drawn.
Recommended video:
Introduction to Confidence Intervals
Sample Proportion
The sample proportion is the ratio of the number of individuals in a sample who have a particular characteristic to the total number of individuals in that sample. In this case, it refers to the percentage of survey respondents who claimed they voted, which is essential for calculating the confidence interval.
Recommended video:
Sampling Distribution of Sample Proportion
Margin of Error
The margin of error quantifies the uncertainty in the estimate of a population parameter based on a sample. It is calculated using the standard error of the sample proportion and reflects how much the sample proportion might differ from the true population proportion, influencing the width of the confidence interval.
Recommended video:
Finding the Minimum Sample Size Needed for a Confidence Interval
Watch next
Master Constructing Confidence Intervals for Proportions with a bite sized video explanation from Patrick
Start learningRelated Videos
Related Practice
Textbook Question