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Multiple Choice
A woman is a carrier for red-green color blindness, a sex-linked trait. Her husband is normal (not color-blind) for this trait. What are the chances that their newborn daughter will be red-green color-blind?
A
25%
B
50%
C
75%
D
100%
E
0%
Verified step by step guidance
1
Understand that red-green color blindness is a sex-linked trait, specifically linked to the X chromosome. This means that the gene responsible for this condition is located on the X chromosome.
Recognize that a woman who is a carrier for red-green color blindness has one normal X chromosome and one X chromosome with the color blindness allele. Her genotype can be represented as XCXc, where XC is the normal allele and Xc is the allele for color blindness.
The husband is normal for this trait, meaning he has a normal X chromosome and a Y chromosome. His genotype is XCY.
When they have a daughter, she will inherit one X chromosome from each parent. The possible combinations for the daughter are: XCXC (normal) or XCXc (carrier).
Since the daughter inherits one X chromosome from her father, which is normal (XC), she cannot be color-blind because she would need two X chromosomes with the color blindness allele (XcXc) to express the trait. Therefore, the chance of their daughter being red-green color-blind is 0%.