Identify each of the following pairs of Fischer projections as enantiomers or identical compounds:
c.

Question

Identify each of the following pairs of Fischer projections as enantiomers or identical compounds:

c. Fischer projections of two compounds labeled as

Accepted Answer

Welcome back everyone. To another video are the fisher projections shown below identical or in an tumor. The first goal in this problem is to understand whether or not we have chiral carbon atoms present in our structures and chiral carbon atoms, well, those are asymmetric centers that have four different subscriptions or basically groups. We can clearly see that the central carbon has four different substitutions. We can label them as follows. Bromine is substitution number one followed by ch two chtoh which is substitution number two. Then we have the muscle substituent and hydrogen and we have exactly the same substituents for the second fissure projection. Those are four different subscriptions, meaning the two structures, they have a chiral carbon atom, right. So now the second step is to understand if they are non super imposable mirror images of each other, because if they are, then we can clearly say that they are in an tumor, if they are super imposable in some way, they are identical. So to clearly understand that these structures are not in an tumors and they are actually identical. We can just compare the relative positions of each substituent. We notice that Bromine is on the left for each case, the metal group is at the bottom, siege to siege to a waitress at the top. And hygiene is on the right side of the fissure projection. So that means they are identical. And we can essentially verify that by simply stating that in fissure projections, the vertical bonds are dashed bonds and the horizontal ones are wedges. So we don't need to try and draw the mirror images of them. Because without any additional transformation, we can see that those structures are immediately super imposable. If they have a chiral center and they are super imposable, then they cannot be in anmer, they represent the same structure. So in this case, we can state that they are identical. That would be our final answer. And thank you for watching.

Identify each of the following pairs of Fischer projections as enantiomers or identical compounds:
c.

Verified video answer for a similar problem:

Key Concepts

Fischer Projections

Enantiomers

Identical Compounds

Identify each of the following pairs of Fischer projections as enantiomers or identical compounds:c.

Verified video answer for a similar problem:

Key Concepts

Fischer Projections

Enantiomers

Identical Compounds

Identify each of the following pairs of Fischer projections as enantiomers or identical compounds:
c.