Identify each of the following pairs of Fischer projections as enantiomers or identical compounds:
a.

Question

Identify each of the following pairs of Fischer projections as enantiomers or identical compounds:

a. Fischer projections of two compounds labeled as

Accepted Answer

Welcome back, everyone indicate whether the fissure projections shown below are identical or in an tumors. The first step in such a problem is to understand if we have any chiral carbon atoms. Let's recall that the chiral position is simply the carbon atom with four different substituents. If we were to label them, then we would get Bromine substi number one, then we would get CHTOH. That's our second substituent followed by CH to CHTOH, that's our third substituent. And then we have hydrogen. So those are four different substituents, meaning the central carbon atom is chiral and this makes the compound itself chiral as well. Since it doesn't have any internal plane of symmetry, looking at the second structure, we can label those exactly same substituents as one, 23 and four. Now, if they have a chiral carbon atom, our goal is to understand if they can be in an tumor. Let's recall that in an tumor are non superimposable mirror images of each other. Now, in this case, what we can do is simply draw a vertical line between the two fisher projections. And we want to understand if those are mirror images of each other and indeed, they are, we can see that hygen at or basically hygen labeled as four is reflected, right? Then we have substituent C which is reflected substituent three and eventually Bromine which is substituent number one, right. So we have two structures which are mirror images of each other. And if we were to flip the second facial projection, we would notice that hydrogen would simply appear on the right and Bromine would appear on the left. Now, does that mean that they are super imposable? Well, the answer is simply no, because according to Fisher projections, the vertical bonds are dashed bonds, right? And if we were to flip the second Fisher projection, those dashed bonds would become a wedges. And this simply means that they are non super imposable. So they are in Antium and that's it. We have our final answer. Thank you for watching.

Identify each of the following pairs of Fischer projections as enantiomers or identical compounds:
a.

Verified video answer for a similar problem:

Key Concepts

Fischer Projections

Enantiomers

Identical Compounds

Identify each of the following pairs of Fischer projections as enantiomers or identical compounds:a.

Verified video answer for a similar problem:

Key Concepts

Fischer Projections

Enantiomers

Identical Compounds

Identify each of the following pairs of Fischer projections as enantiomers or identical compounds:
a.