Locate fluorine (F) on the partial periodic table provided in Fig...

Question

Locate fluorine (F) on the partial periodic table provided in Figure 2.2. Predict its relative electronegativity compared to hydrogen, sodium, and oxygen. State the number and type of bond(s) you expect it would form if it reacted with sodium (Na).

Accepted Answer

Welcome back. Let's look at our next question. It says which of the following elements has the highest electro negativity? Well, let's recall from our content videos that electro negativity is the ability to attract oops electrons in a chemical bond. So when two different atoms are bonded together, which one has more ability to attract the electrons. And in a non scientific way you could think of it as which element wants and electron more. So very non scientific. But sometimes helpful to think of it that way when you're trying to remember these things. So there's actually a numerical value for electro negativity. If you have access to that, that's called the Pauling scale. So if you have access to those numbers, you could look them up for each element and see which is highest. But we can use our periodic table and the trends on the periodic table to figure that out. Even if we don't have an actual number for our electro negativity. So let's look at sort of my silhouette of a periodic table here. And when we look for our answer choices, let's pretend we looked on our periodic table and looked them all up and we see that they're all in this column seven and I'm gonna go ahead and label where they are. I've seen look them all up their locations here and here's browning choice A choice B is chlorine, choice C. Is iodine and choice D. Is flooring. So when I know, look at my periodic table, there are certain trends of electro negativity on it. So going from left to right electro negativity increases Up to Row seven. That's because the number of protons in the nucleus is increasing. So your nucleus is getting more positive. And as you fill the outer shell of electrons you get closer and closer to a full shell. And therefore um the element will want that electron more for lack of a better word because it's more stable with a full outer shell. So the closer you are to that full shell um the stronger a pole that element will have on an electron and a chemical bond. Obviously then once you get to group ate the noble gasses, they don't form bonds with other atoms because they've got a full outer shell. Well all of our elements here are in the same column. So that left to right trend doesn't matter to us. However, we know that as we go from bottom to top, electro negativity increases or we could say it decreases as you go down. This is because as the elements get bigger as the atoms get bigger, that positively charged nucleus is going to be farther and farther away from the outer shells of the electron because the atoms getting bigger so the outer electrons will be farther and farther away and therefore that positively charged nucleus will have a weaker pull on the electrons due to distance. So as we go up and as we go right election negativity will increase. But when we look at our answer choices, we've got flooring here and the very top of our column. So by that trend of electric negativity increasing as you go up, flooring choice D. Is our correct answer, and it's the most electro negative element. And in fact, flooring is actually the most electrical negative element in the entire periodic table. So we'll just we know our other choices are not correct. So cross out roaming chlorine and iodine choice D. Flooring has the highest election negativity of all the elements here. Thanks for watching. See you in the next video.

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Locate fluorine (F) on the partial periodic table provided in Figure 2.2. Predict its relative electronegativity compared to hydrogen, sodium, and oxygen. State the number and type of bond(s) you expect it would form if it reacted with sodium (Na).

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