Multiple Choice
Emily is organizing her closet. She has 15 shirts left to hang but has space in one section for 6 shirts. How many ways could she hang shirts in that section?
4. Probability
Counting
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From a class of 28 students, in how many ways could a teacher select 4 students to lead the class discussion?
A
B
C
Verified step by step guidance1
Understand that this is a combination problem where the order of selection does not matter. We need to calculate the number of ways to choose 4 students from a class of 28.
Use the combination formula: \( C(n, k) = \frac{n!}{k!(n-k)!} \), where \( n \) is the total number of items to choose from, and \( k \) is the number of items to choose.
Substitute the values into the formula: \( C(28, 4) = \frac{28!}{4!(28-4)!} \).
Calculate the factorials: \( 28! \), \( 4! \), and \( 24! \).
Simplify the expression by canceling out the common terms in the numerator and the denominator to find the number of combinations.
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