Triethylenemelamine (TEM) is an antitumor agent. Its activity is due to its ability to cross-link DNA.
b. Explain why it can cross-link DNA.
Triethylenemelamine (TEM) is an antitumor agent. Its activity is due to its ability to cross-link DNA.
b. Explain why it can cross-link DNA.
In Section 10.12, we saw that S-adenosylmethionine (SAM) methylates the nitrogen atom of noradrenaline to form adrenaline, a more potent hormone. If SAM methylates an OH group attached to the benzene ring instead, it completely destroys noradrenaline's activity.
b. Which reaction is more apt to occur, methylation on nitrogen or methylation on oxygen?
Dimethylamine, (CH3)2NH, has a molecular weight of 45 and a boiling point of 7.4 °C. Trimethylamine, (CH3)3N, has a higher molecular weight (59) but a lower boiling point (3.5 °C). Explain this apparent discrepancy.
Rank the following substituted anilines from most basic to least basic:
Rank each set of compounds in order of increasing boiling points.
(a) triethylamine, di-n-propylamine, n-propyl ether
(b) ethanol, dimethylamine, dimethyl ether
(c) diethylamine, diisopropylamine, trimethylamine
In each pair of compounds, select the stronger base, and explain your choice.
(a) HOCH2CH2NH2 or CH3CH2NH2
(b) PhNH2 or PhCH2NH2
Within each structure, rank the indicated nitrogens by increasing basicity.
(c)
Within each structure, rank the indicated nitrogens by increasing basicity.
(a)
(b)
Rank each set of compounds in order of increasing basicity.
(d) pyrrole, imidazole, 3-nitropyrrole
Rank each set of compounds in order of increasing basicity.
(c) aniline, pyrrole, pyridine, piperidine
Rank each set of compounds in order of increasing basicity.
(b) aniline, p-methylaniline, p-nitroaniline
Predict the products of the following reactions:
(a) excess NH3 + Ph–CH2CH2CH2Br →
Propose a mechanism to show the individual alkylations that form this quaternary ammonium salt.
What is the major product of the following reactions?
c.
Draw the product formed when pyridine reacts with ethyl bromide