Draw the structural formula for the product in each of the following reactions:
b.

Question

Draw the structural formula for the product in each of the following reactions:

b. Structural formula of an alkene reacting with water and an acid catalyst, showing the reactants and products.

Accepted Answer

All right. Hi, everyone. So this question is asking us to give the structure of the product resulting from the reaction shown below. Here, we have three methyl one butane reacting with water in the presence of acid as a catalyst. So recall that the combination of an alkene reacting with water in the presence of an acid is an example of a hydration reaction of an alkane. And recall that a hydration reaction involves the addition of water across both carbons of the starting double bond. So in other words, right, one carbon atom receives a hydrogen attached to it and the other receives a hydroxy or oh group attached to it resulting in the formation of an alcohol as our final product. But the question is where exactly does the hydroxy group attach itself to? It has to be one of the two carbons of the double wand. But the question is which one? Well, to answer this question, we have to recall that the hydration of an alkene is an example of Markov Niko addition. Now, Markov Kov or the Makov rule specifically addresses all keys that are asymmetrical of which three metal one beine is an example, because notice how the two carbons in the double bond have different substituents attached to them. So therefore, this a is asymmetrical. So when it comes to an asymmetrical all keen, according to Markov Niko's rule, the hydroxy group would add on to the more substituted carbon. So what does that mean? Right, the more substituted carbon refers to the carbon of the starting all keen that has less hydrogen atoms attached to it. So if I consider the structure given right, carbon one has two hydrogens or as carbon two has only one, so therefore, carbon two is more substituted and that is where the hydroxy group would be attached. So if I scroll down here to draw my final product, it's worth mentioning that the carbon backbone is not going to change. I'm going to have the same four carbon chain with the same methyl substituent. But the primary difference now is that there will now be a single bond in between carbon one and two. So carpet one will obtain an additional hydrogen. So it's ach three connecting to carbon two where is carbon three and four remain the same as does the methyl substituent. So here attached to carbon two, which is more substituted goes the hydroxy group or the oh group. This means that my final product is going to be three metal two butanol and there you have it. So here is your final answer. And before we go, just for the record if the starting alkene was symmetrical, meaning both carbons had the same substituents, then the hydroxy group would have added on to either carbon. But in this case, it was asymmetrical. So with that being said, thank you so very much for watching. And I hope you found this helpful.

Draw the structural formula for the product in each of the following reactions:
b.

Verified video answer for a similar problem:

Key Concepts

Structural Formula

Reaction Mechanism

Functional Groups

Draw the structural formula for the product in each of the following reactions:b.

Verified video answer for a similar problem:

Key Concepts

Structural Formula

Reaction Mechanism

Functional Groups

Draw the structural formula for the product in each of the following reactions:
b.