In Exercises 61–76, solve each absolute value equation or indicate that the equation has no solution. |x + 1| + 5 = 3

Solve each equation in Exercises 65–74 using the quadratic formula. x² - 6x + 10 = 0

In Exercises 71–78, solve each equation. Then determine whether the equation is an identity, a conditional equation, or an inconsistent equation. 4(x + 5) = 21 + 4x

Exercises 73–75 will help you prepare for the material covered in the next section. Simplify: √18 - √8

Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. The ordered pair (2, 5) satisfies 3y - 2x = - 4.

In Exercises 71–78, solve each equation. Then determine whether the equation is an identity, a conditional equation, or an inconsistent equation. 10x + 3 = 8x + 3

In Exercises 75–82, compute the discriminant. Then determine the number and type of solutions for the given equation. $x^2-4x-5=0$

In Exercises 59–94, solve each absolute value inequality. |(2x + 2)/4| ≥ 2

In Exercises 61–76, solve each absolute value equation or indicate that the equation has no solution. |2x - 1| + 3 = 3

Solve each equation by the method of your choice. $3x^2-7x+1=0$

Exercises 73–75 will help you prepare for the material covered in the next section. Rationalize the denominator: (7 + 4√2)/(2 - 5√2).

In Exercises 71–78, solve each equation. Then determine whether the equation is an identity, a conditional equation, or an inconsistent equation. 5x + 7 = 2x + 7

Solve each equation by the method of your choice. $(x-3{)}^2-25=0$

In Exercises 59–94, solve each absolute value inequality. |3 - (2/3)x| > 5

The rule for rewriting an absolute value equation without absolute value bars can be extended to equations with two sets of absolute value bars: If u and v represent algebraic expressions, then |u| = |v| is equivalent to u = v or u = - v. Use this to solve the equations in Exercises 77–84. |3x - 1| = |x + 5|

In Exercises 75–82, compute the discriminant. Then determine the number and type of solutions for the given equation. $2x^2-11x+3=0$

List the quadrant or quadrants satisfying each condition. x³ > 0 and y³ <0

In Exercises 59–94, solve each absolute value inequality. 3|x - 1| + 2 ≥ 8

The rule for rewriting an absolute value equation without absolute value bars can be extended to equations with two sets of absolute value bars: If u and v represent algebraic expressions, then |u| = |v| is equivalent to u = v or u = - v. Use this to solve the equations in Exercises 77–84. |4x - 3| = |4x - 5|

Compute the discriminant. Then determine the number and type of solutions for the given equation. x² - 2x + 1 = 0

Solve each absolute value inequality. 5|2x + 1| - 3 ≥ 9

The rule for rewriting an absolute value equation without absolute value bars can be extended to equations with two sets of absolute value bars: If u and v represent algebraic expressions, then |u| = |v| is equivalent to u = v or u = - v. Use this to solve the equations in Exercises 77–84. $\mid x^2-6\mid =\mid 5x\mid$

In Exercises 59–94, solve each absolute value inequality. - 2|x - 4| ≥ - 4

Compute the discriminant. Then determine the number and type of solutions for the given equation. x² - 3x - 7 = 0

The rule for rewriting an absolute value equation without absolute value bars can be extended to equations with two sets of absolute value bars: If u and v represent algebraic expressions, then |u| = |v| is equivalent to u = v or u = - v. Use this to solve the equations in Exercises 77–84. $\mid 2x^2-4\mid =\mid 2x^2\mid$

Solve each equation in Exercises 83–108 by the method of your choice. 2x² - x = 1

Solve each absolute value inequality. - 4|1 - x| < - 16

In Exercises 59–94, solve each absolute value inequality. 3 ≤ |2x - 1|

Solve each equation in Exercises 83–108 by the method of your choice. $5x^2+2=11x$