105. Motion Along a Line The graphs in Exercises 105 and 106 show the position s=f(t) of an object moving up and down on a coordinate line. At approximately what times is the (c) Acceleration equal to zero?
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 39m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
4. Applications of Derivatives
Motion Analysis
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Given the position equation s(t), calculate the average velocity (in meters per second) based on the given interval, and the instantaneous velocity (in meters per second) at the end of the time interval.
s(t)=9t−t2, 0≤t≤3
A
Average: vavg=6sm, Instantaneous: v(3)=3sm
B
Average: vavg=10sm , Instantaneous: v(3)=18sm
C
Average: vavg=18sm , Instantaneous: v(3)=10sm
D
Average: vavg=6sm , Instantaneous: v(3)=0

1
To find the average velocity over the interval [0, 3], use the formula for average velocity: \( v_{avg} = \frac{s(t_2) - s(t_1)}{t_2 - t_1} \), where \( t_1 = 0 \) and \( t_2 = 3 \).
Calculate \( s(0) \) using the position function \( s(t) = 9t - t^2 \). Substitute \( t = 0 \) into the equation to find \( s(0) \).
Calculate \( s(3) \) using the position function \( s(t) = 9t - t^2 \). Substitute \( t = 3 \) into the equation to find \( s(3) \).
Substitute \( s(0) \) and \( s(3) \) into the average velocity formula \( v_{avg} = \frac{s(3) - s(0)}{3 - 0} \) to find the average velocity over the interval.
To find the instantaneous velocity at \( t = 3 \), calculate the derivative of the position function \( s(t) = 9t - t^2 \) to get the velocity function \( v(t) = \frac{d}{dt}(9t - t^2) \). Then, substitute \( t = 3 \) into \( v(t) \) to find \( v(3) \).
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Motion Analysis practice set
