Ch. 36 - Resource Acquisition and Transport in Vascular Plants

Campbell - Campbell Biology 12th Edition

Urry12th EditionCampbell BiologyISBN: 9785794169850Not the one you use?Change textbook

Urry 12th Edition

Ch. 36 - Resource Acquisition and Transport in Vascular Plants

Problem 5

Chapter 36, Problem 5

What would enhance water uptake by a plant cell?
a. Decreasing the Ψ of the surrounding solution
b. Positive pressure on the surrounding solution
c. The loss of solutes from the cell
d. Increasing the Ψ of the cytoplasm

Verified step by step guidance

Understand the concept of water potential (Ψ), which is a measure of the potential energy in water and drives the movement of water. Water moves from areas of higher water potential to areas of lower water potential.

Recognize that the water potential of a solution is affected by solute concentration and pressure. The formula for water potential is Ψ = Ψs + Ψp, where Ψs is the solute potential and Ψp is the pressure potential.

Consider option a: Decreasing the Ψ of the surrounding solution would mean lowering its water potential, making it more negative. This would enhance water uptake by the plant cell because water would move from the higher water potential inside the cell to the lower water potential outside.

Evaluate option b: Positive pressure on the surrounding solution would increase the Ψp, potentially increasing the water potential of the surrounding solution, which might not enhance water uptake as water moves from higher to lower potential.

Analyze option c and d: The loss of solutes from the cell (option c) would increase the Ψs inside the cell, potentially reducing water uptake. Increasing the Ψ of the cytoplasm (option d) would make the water potential inside the cell higher, which would not enhance water uptake as water moves from higher to lower potential.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.

Video duration:

50s

Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Water Potential (Ψ)

Water potential (Ψ) is a measure of the potential energy in water, influencing the direction of water movement. It is affected by solute concentration and pressure, with water moving from areas of higher to lower water potential. Understanding Ψ is crucial for determining how water uptake by plant cells is influenced by surrounding conditions.

Osmosis

Osmosis is the passive movement of water across a semipermeable membrane from a region of lower solute concentration to higher solute concentration. In plant cells, osmosis drives water uptake, with water moving into cells when the external environment has a lower water potential than the cell's interior, facilitating nutrient absorption and cell turgor.

Pressure Potential

Pressure potential is a component of water potential that accounts for the physical pressure exerted on water within plant cells. Positive pressure can increase water potential, promoting water movement into cells. Understanding how pressure potential interacts with solute concentration helps explain how external pressures can enhance or inhibit water uptake in plant cells.

Recommended video:

Guided course

11:58

Pressure Potential and Turgidity

Related Practice

Textbook Question

Which structure or compartment is part of the symplast?

a. The interior of a vessel element

b. The interior of a sieve tube

c. The cell wall of a mesophyll cell

d. An extracellular air space

Textbook Question

Movement of phloem sap from a source to a sink

a. Occurs through the apoplast of sieve-tube elements

b. Depends ultimately on the activity of proton pumps

c. Depends on tension, or negative pressure potential

d. Results mainly from diffusion

Textbook Question

Photosynthesis ceases when leaves wilt, mainly because

a. The chlorophyll in wilting leaves is degraded.

b. Accumulation of CO₂in the leaf inhibits enzymes.

c. Stomata close, preventing CO₂ from entering the leaf.

d. Photolysis, the water-splitting step of photosynthesis, cannot occur when there is a water deficiency.

Textbook Question

A plant cell with a Ψ_S of −0.65MPa maintains a constant volume when bathed in a solution that has a Ψ_S of −0.30MPa and is in an open container. The cell has a

a. Ψ_P of +0.65MPa

b. Ψ of −0.65MPa

c. Ψ_P of +0.35MPa

d. Ψ_P of 0 MPa

views

Textbook Question

Compared with a cell with few aquaporin proteins in its membrane, a cell containing many aquaporin proteins will

a. Have a faster rate of osmosis

b. Have a lower water potential

c. Have a higher water potential

d. Accumulate water by active transport

Textbook Question

Which of the following would tend to increase transpiration?

a. Spiny leaves

b. Sunken stomata

c. A thicker cuticle

d. Higher stomatal density

What would enhance water uptake by a plant cell? a. Decreasing the Ψ of the surrounding solution b. Positive pressure on the surrounding solution c. The loss of solutes from the cell d. Increasing the Ψ of the cytoplasm

Verified video answer for a similar problem:

Key Concepts

Water Potential (Ψ)

Osmosis

Pressure Potential

What would enhance water uptake by a plant cell?
a. Decreasing the Ψ of the surrounding solution
b. Positive pressure on the surrounding solution
c. The loss of solutes from the cell
d. Increasing the Ψ of the cytoplasm