Using the bond-dissociation energies in Table 5.6,
(a) predict whether or not an iodine radical would be selective for forming a single radical propane.
Using the bond-dissociation energies in Table 5.6,
(a) predict whether or not an iodine radical would be selective for forming a single radical propane.
What is the major product of the reaction in Problem 7 when the alkane reacts with Cl2 instead of with Br2? Disregard stereoisomers.
Radical addition to alkenes is not effective for the synthesis of iodo- and chloroalkanes. Using your knowledge of the mechanism of this reaction, along with bond dissociation energies, explain why the radical additions of HI and HCl are not effective. (Assume ∆H = 65 kcal/ mol for the C–C π bond.)
The benzene ring alters the reactivity of a neighboring group in the benzylic position much as a double bond alters the reactivity of groups in the allylic position.
Benzylic cations, anions, and radicals are all more stable than simple alkyl intermediates.
b. Toluene reacts with bromine in the presence of light to give benzyl bromide. Propose a mechanism for this reaction.
Show how the following compounds could be prepared from 2-methylpropane:
a. 2-bromo-2-methylpropane
Draw the products of the following reactions, including all stereoisomers:
d.
When a student attempted a bromination to produce compound A, they generated compound B instead. Rationalize the formation of B using the arrow-pushing formalism.