Match the following ATP yields to reactions a to g:
1.5 ATP 2.5 ATP 7 ATP 10 ATP
12 ATP 32 ATP 36 ATP
d. Acetyl CoA goes through one turn of the citric acid cycle.

Question

Match the following ATP yields to reactions a to g:

1.5 ATP 2.5 ATP 7 ATP 10 ATP

12 ATP 32 ATP 36 ATP

d. Acetyl CoA goes through one turn of the citric acid cycle.

Accepted Answer

All right. Hello everyone. So this question is asking us what is the A TP yield when three molecules of acetyl coa go through the citric acid cycle. So for this question, recall first and foremost, that Aceto coa produces much more than A TP. And because it produces more than at P, we have to know exactly what it is that's produced and then find all of the ATP that's produced from each product. So for every turn of the citric acid cycle, one molecule of Aceto coa produces three molecules of NH one molecule of FA H two and one equivalent of GTP, which is equivalent to A P. And so here, in addition to taking into account the fact that we already have one equivalent of GTP, which is equivalent to A TP, we have to understand how much A TP is produced from an A DH and FA DH too. So more math is going to be necessary. Let's start with N A DH. So our given is that we have three molecules of N A DH produced from one equivalent of Aceto Coa. And so here recall that one molecule of NAH produces approximately 2.5 A P. So we can treat that as a conversion factor. And so because of that, we multiply three by 2.5. And as a result, we see that 7.5 molecules of ATP are produced per one equivalent of Aceto Coet because our three N A molecules came from a pseudo coa in the first place. But we also have to take into account our FA H too. So we have one FA DH two and that if you recall produces about 1.5 molecules of ATP so R one fa DH two is going to yield 1.5 molecules of ATP per one aceto coa. And at this point, we can go ahead and add everything together to find the total at P per Oops mentor, write a TP. Her won Acito Coet. So that's the sum of 7.5 from N A DH 1.5 from FA DH two and the one molecule of GTP that we had discussed in the beginning. So 7.5 added to 1.5 and added to one ultimately equals 10 molecules of A TP per one equivalent of aceto coa. However, we have three molecules of Aceto coa. So if we take this number, that's 10 and multiply that by three, our real answer is that we get 30 molecules of A TP from this process. And so 30 A TP is our correct answer and there you have it. So with that being said, thank you so very much for watching. And I hope we found this helpful.

Match the following ATP yields to reactions a to g:
1.5 ATP 2.5 ATP 7 ATP 10 ATP
12 ATP 32 ATP 36 ATP
d. Acetyl CoA goes through one turn of the citric acid cycle.

Verified video answer for a similar problem:

Key Concepts

ATP Yield in Cellular Respiration

Citric Acid Cycle (Krebs Cycle)

Oxidative Phosphorylation

Match the following ATP yields to reactions a to g:1.5 ATP 2.5 ATP 7 ATP 10 ATP12 ATP 32 ATP 36 ATPd. Acetyl CoA goes through one turn of the citric acid cycle.

Verified video answer for a similar problem:

Key Concepts

ATP Yield in Cellular Respiration

Citric Acid Cycle (Krebs Cycle)

Oxidative Phosphorylation

Match the following ATP yields to reactions a to g:
1.5 ATP 2.5 ATP 7 ATP 10 ATP
12 ATP 32 ATP 36 ATP
d. Acetyl CoA goes through one turn of the citric acid cycle.