Draw the condensed structural formula for the alcohol formed when each of the following is reduced by hydrogen in the presence of a nickel catalyst:
a. ethyl propyl ketone

Question

Draw the condensed structural formula for the alcohol formed when each of the following is reduced by hydrogen in the presence of a nickel catalyst:

a. ethyl propyl ketone

Accepted Answer

Welcome back. Here's our next problem provide the alcohol produced by the given reaction using condensed structural formula reduction of bey ethyl ketone by hydrogen in the presence of a palladium catalyst. So let's think about the compound we're starting with and then the reaction we're going through. So this is the format. Uh the format of the name we're given is a common name rather than Iupac name. So we have beauty ethyl ketone. So in the common name system for ketones, you have your two R groups named and then ketone. So recall that a ketone is in the format of R bonded to a carbonel group bonded to our prime. So carbonel group with alkyl groups on either side. So in this case, we'll put our carbonel group. Now we have an ethyl group. So that would be a two carbon chain. On one side, we'll go ahead and draw it as a condensed formula. So we'll have a CH two and then CH three, put that on the left side and then on the right side of our carbonel group, we have beauty which should be four carbons. So ch two ch two, ch two, ch three. So total, we have two carbons from the ethyl group, one from the Carbonell and then four from the beetle giving us seven carbons. So our IPAC name would be three heptagon. Note that our carbon carbon has no hydrogen since it has four bonds. So let's look at the general format of this reaction. We have a reduction of a ketone by hydrogen in the presence of this catalyst. So we add H two gas to a ketone. This palladium catalyst, we have a hydrogen added to the oxygen and the carbon of our carbon group recall that reduction in organic chemistry sense reduces the number of C bonds by adding hydrogen or removing oxygen. In this case, we're adding hydrogen and we're reducing the number of co bonds since we're going from a single or excuse me, from a double bond, double co bond to a single co bond. So we reduce that ketone and we end up with a secondary alcohol. So we have the R group, then our carbon, it now has a single bond to an O group. And then our hydrogen has been added to the carbon and then our, our prime. So we have the secondary alcohol as our product. So in terms of our own formula here, our own reactant of our Beyle ethyl ketone, we add hydrogen of our palladium catalyst. And let's write out that condensed structural formula for our product. So we have that two carbon ethyl groups C three CH two, we'll go ahead and draw bonds between them. Then the carbonel group has become an alcohol. So we have C H and then the carbon has an oh. And then, so let's make sure that we have four bonds here for the carbon, one for each R group, one for the oxygen and one for the hydrogen. Yes, we do. And then we have our beetle group ch two ch two ch two CH three. So again, total of 1234567 carbons with an oh group on the third carbon. So there's our condensed structural formula and we will have three Hepton all as the Iupac name of this product. See you in the next video.

Draw the condensed structural formula for the alcohol formed when each of the following is reduced by hydrogen in the presence of a nickel catalyst:
a. ethyl propyl ketone

Verified video answer for a similar problem:

Key Concepts

Reduction Reaction

Nickel Catalyst

Condensed Structural Formula

Draw the condensed structural formula for the alcohol formed when each of the following is reduced by hydrogen in the presence of a nickel catalyst:a. ethyl propyl ketone

Verified video answer for a similar problem:

Key Concepts

Reduction Reaction

Nickel Catalyst

Condensed Structural Formula

Draw the condensed structural formula for the alcohol formed when each of the following is reduced by hydrogen in the presence of a nickel catalyst:
a. ethyl propyl ketone