Draw the condensed structural formula, or line-angle formula, if cyclic, for each of the following:
d. 3-chloro-1-butyne

Question

Draw the condensed structural formula, or line-angle formula, if cyclic, for each of the following:

d. 3-chloro-1-butyne

Accepted Answer

Hi, everyone. Welcome back. Our next question says, draw the condensed structural formula of 44 di bromo one hex sign. So which kind of formula is the condensed structural formula? That's that sort of hybrid one where we show many of the bo we show the bonds and many of the atoms specifically. So we want to show connections between atoms with lines. We have bonds shown as lines, atoms are written out including carbon atoms, but ch groups are shown as groups of letters. So we just have things like CH three or CH two. So you don't show all the bonds between carbon and hydrogen. So it's a little more detailed than a skeletal structure, but you don't, you're not as cluttered as the expanded structure that shows all of the hydrogen bonds as well or I shouldn't say hydrogen bonds, that's something else the bonds of hydrogen to other atoms. So we want to make one of these condensed structural formulas for our 44 di bromo one hex sign. So we have that ending Yne, we know we have a triple bond that is on carbon one. So from carbon one that's triple bonded to carbon two and we have a hack sign. So we have six carbons in that chain. So let's start by writing six CS and the bonds between them knowing that the bonds between one and two are a triple bond, everything else is a single bond. So we'll write C and then our three lines for a triple bond and then another c now I'm going to leave a space in case there's any hydrogens. Although in this case, I don't need to leave a space when I have a triple bond and I have an internal carbon like this, that's already four bonds around my carbon. It won't take any hydrogens. So I don't need to leave a space there. So then my third carbon. So I'm on to carbon three, leave a space. Carbon four, leave a space. Carbon five, leave a space carbon six. So now I will fill in my substituents. I've got my triple bond there. I've got my six carbons and I have two bromine atoms on carbon four. They're both on the same carbon. So let's count our carbons to number four, 1234. Here's carbon four and it has two B Romines. So one line up from the carbon, right br another line down another br now my last step is fill in the hydrogen atoms. So I look at each of my carbons. How many bonds does it have and fill in hydrants as hydrogens to give each of them four bonds. So carbon one has a triple bond, that's three but nothing else. So it gets one hydrogen in front of it. So HC triple bond c no hydrogens there, single bond to ac this carbon is internal and has just two bonds, no substituents. So that is H two goes there. My next carbon has the two bromine substituents. It doesn't get any hydrogens because it has two bonds to carbons in the chain as well. Our next carbon, no substituents, it's internal. So it gets two hydrogens and then we have this last carbon with no substituents. So that gets three. So my condensed structural formula for 44 di bromo one hexane is HC and then triple bond to another c single bond to CH two, single bond to C with a bromine up top a bromine, down the bottom single bond to CH two, single bond to CH three. See you in the next video.

Draw the condensed structural formula, or line-angle formula, if cyclic, for each of the following:
d. 3-chloro-1-butyne

Verified video answer for a similar problem:

Key Concepts

Condensed Structural Formula

Line-Angle Formula

Alkynes

Draw the condensed structural formula, or line-angle formula, if cyclic, for each of the following:d. 3-chloro-1-butyne

Verified video answer for a similar problem:

Key Concepts

Condensed Structural Formula

Line-Angle Formula

Alkynes

Draw the condensed structural formula, or line-angle formula, if cyclic, for each of the following:
d. 3-chloro-1-butyne