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Ch. 2 - Transmission Genetics
Sanders - Genetic Analysis: An Integrated Approach 3rd Edition
Sanders3rd EditionGenetic Analysis: An Integrated ApproachISBN: 9780135564172Not the one you use?Change textbook
Chapter 2, Problem 30c

A male and a female are each heterozygous for both cystic fibrosis (CF) and phenylketonuria (PKU). Both conditions are autosomal recessive, and they assort independently.
What proportion of the children will be carriers of one or both conditions?

Verified step by step guidance
1
Identify the genotypes of the parents for both traits. Since both are heterozygous for cystic fibrosis (CF) and phenylketonuria (PKU), their genotypes can be represented as Cc for CF and Pp for PKU, where uppercase letters represent the dominant (normal) alleles and lowercase letters represent the recessive (disease) alleles.
Determine the possible gametes each parent can produce. Because the genes assort independently, each parent can produce four types of gametes: C P, C p, c P, and c p, each with equal probability (1/4).
Construct a Punnett square combining the gametes from both parents to find the genotypic combinations of their children. This will result in 16 possible genotype combinations, each with a probability of 1/16.
Classify each genotype according to whether the child is a carrier for CF, PKU, both, or neither. A carrier is heterozygous for the trait (e.g., C c for CF or P p for PKU). Children who are homozygous dominant or homozygous recessive for either trait are not carriers for that trait.
Calculate the proportion of children who are carriers of one or both conditions by summing the probabilities of genotypes that are heterozygous for CF, PKU, or both. Use the Punnett square results to identify these genotypes and add their probabilities accordingly.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Autosomal Recessive Inheritance

Autosomal recessive traits require two copies of the mutant allele for the phenotype to be expressed. Carriers have one normal and one mutant allele but do not show symptoms. Understanding this helps determine the genotypes and phenotypes of offspring when both parents are heterozygous carriers.
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Autosomal Pedigrees

Independent Assortment

Independent assortment means that alleles of different genes segregate independently during gamete formation. This principle allows the calculation of combined probabilities for inheriting alleles of two different genes, such as CF and PKU, by multiplying their individual probabilities.
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Gamete Genetics and Independent Assortment

Carrier Probability Calculation

Calculating the proportion of carriers involves determining the likelihood that offspring inherit one mutant allele for either or both conditions. This requires using Punnett squares or probability rules to find the chance of being heterozygous for CF, PKU, or both, excluding affected or non-carrier genotypes.
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Related Practice
Textbook Question

In tomato plants, the production of red fruit color is under the control of an allele R. Yellow tomatoes are rr. The dominant phenotype for fruit shape is under the control of an allele T, which produces two lobes. Multilobed fruit, the recessive phenotype, has the genotype tt. Two different crosses are made between parental plants of unknown genotype and phenotype. Use the progeny phenotype ratios to determine the genotypes and phenotypes of each parent.

 Cross 1 progeny:

3/8 two-lobed, Red

                    3/8 two-lobed, yellow

                    1/8 multilobed, Red

                    1/8 multilobed, Yellow

 Cross 2 progeny:

1/4 two-lobed, Red

                     1/4 two-lobed, yellow

                     1/4 multilobed, Red

                     1/4 multilobed, yellow

Textbook Question

A male and a female are each heterozygous for both cystic fibrosis (CF) and phenylketonuria (PKU). Both conditions are autosomal recessive, and they assort independently.

What proportion of the children of this couple will have neither condition?

Textbook Question

A male and a female are each heterozygous for both cystic fibrosis (CF) and phenylketonuria (PKU). Both conditions are autosomal recessive, and they assort independently.

What proportion of the children will have either PKU or CF but not both?

Textbook Question

Dr. Ara B. Dopsis and Dr. C. Ellie Gans are performing genetic crosses on daisy plants. They self-fertilize a blue-flowered daisy and grow 100 progeny plants that consist of 55 blue-flowered plants, 22 purple-flowered plants, and 23 white-flowered plants. Dr. Dopsis believes this is the result of segregation of two alleles at one locus and that the progeny ratio is 1:2:1. Dr. Gans thinks the progeny phenotypes are the result of two epistatic genes and that the ratio is 9:3:4.

The two scientists ask you to resolve their conflict by performing chi-square analysis on the data for both proposed genetic mechanisms. For each proposed mechanism, fill in the values requested on the form the researchers have provided for your analysis.


Using any of the 100 progeny plants, propose a cross that will verify the conclusion you proposed in part (c). Plants may be self-fertilized, or one plant can be crossed to another. What result will be consistent with the 1:2:1 hypothesis? What result will be consistent with the 9:3:4 hypothesis?

Textbook Question

A woman expressing a dominant phenotype is heterozygous (Dd) for the gene.


What is the probability that the dominant allele carried by the woman will be inherited by a grandchild?

Textbook Question

A woman expressing a dominant phenotype is heterozygous (Dd) for the gene.


What is the probability that two grandchildren of the woman who are first cousins to one another will each inherit the dominant allele?