Multiple ChoiceAccording to the reaction 2 LiOH + FeCl2 → 2 LiCl + Fe(OH)2, how many moles of Fe(OH)2 can be formed from 175.0 mL of 0.227 M LiOH solution?
Multiple ChoiceHow many grams of CaCl2 are formed when 15.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 gas according to the reaction: 2 Ca(OH)2(aq) + 2 Cl2(g) → Ca(OCl)2(aq) + CaCl2(s) + 2 H2O(l)?
Multiple ChoiceHow many grams of KCl(s) are produced from the thermal decomposition of KClO3(s) when 25.0 mL of O2(g) is produced at 25°C and 1.00 atm pressure according to the chemical equation: 2 KClO3(s) → 2 KCl(s) + 3 O2(g)?
Multiple ChoiceHow many grams of Li3N can be formed from 1.75 moles of Li based on the following balanced chemical equation of the reaction? Assume an excess of nitrogen. 6 Li(s) + N2(g) → 2 Li3N(s)
Multiple ChoiceHow many grams of Li3N can be formed from 1.75 moles of Li, assuming an excess of nitrogen? The balanced equation is: 6 Li(s) + N2(g) → 2 Li3N(s).
Multiple ChoiceHow many grams of NaOH (molar mass = 40.0 g/mol) are there in 500 mL of a 0.175 M NaOH solution?
Multiple ChoiceHow many grams of calcium hydride (CaH2) are required to produce 4.56 L of hydrogen gas (H2) at 25.0 °C and 0.975 atm according to the reaction: CaH2(s) + 2H2O(l) → Ca(OH)2(aq) + 2H2(g)?
Multiple ChoiceHow many grams of chlorine gas (Cl2) can be produced from the decomposition of 73.4 g of AuCl3 according to the reaction: 2AuCl3 → 2Au + 3Cl2?
Multiple ChoiceHow many grams of hydrogen gas are required if the goal is to form 5.0 x 10⁵ molecules of ammonia? Assume the nitrogen gas is in excess. N₂ (g) + 3 H₂ (g) → 2 NH₃ (g)
Multiple ChoiceHow many grams of water are produced when 0.23 moles of O2 react with excess H2 according to the balanced equation: 2H2 + O2 → 2H2O?
Multiple ChoiceHow many grams of zinc metal are required to produce 3.5 liters of hydrogen gas at STP according to the chemical equation Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g)?
Multiple ChoiceHow many liters of dry chlorine gas can be obtained at 40.0°C and 787 mm Hg from the reaction of an aqueous solution containing 9.41 g of HCl with 2.01 g of KMnO4(s) according to the following equation? 2 KMnO4(s) + 16 HCl(aq) → 8 H2O(l) + 2 MnCl2(aq) + 5 Cl2(g)
Multiple ChoiceHow many milliliters of 0.200 M FeCl3 are needed to react with an excess of Na2S to produce 0.172 g of Fe2S3 if the percent yield for the reaction is 65.0%?
Multiple ChoiceHow many milliliters of 0.200 M FeCl3 are needed to react with an excess of Na2S to produce 1.38 g of Fe2S3 if the percent yield for the reaction is 65.0%? 3 Na2S(aq) + 2 FeCl3(aq) → Fe2S3(s) + 6 NaCl(aq)