Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

3. Chemical Reactions

Stoichiometry

General Chemistry

3. Chemical Reactions

Stoichiometry

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Multiple Choice

How many grams of chlorine gas (Cl2) can be produced from the decomposition of 73.4 g of AuCl3 according to the reaction: 2AuCl3 → 2Au + 3Cl2?

58.8 g

73.4 g

25.0 g

39.2 g

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Verified step by step guidance

Start by writing the balanced chemical equation for the decomposition reaction: 2AuCl3 → 2Au + 3Cl2. This equation shows that 2 moles of AuCl3 produce 3 moles of Cl2.

Calculate the molar mass of AuCl3. The molar mass is the sum of the atomic masses of gold (Au), chlorine (Cl), and the stoichiometry of the compound: M(AuCl3) = M(Au) + 3 × M(Cl). Use the periodic table to find these values.

Convert the given mass of AuCl3 (73.4 g) to moles using its molar mass. Use the formula: moles of AuCl3 = mass of AuCl3 / molar mass of AuCl3.

Use the stoichiometry of the balanced equation to find the moles of Cl2 produced. According to the equation, 2 moles of AuCl3 produce 3 moles of Cl2. Therefore, moles of Cl2 = (3/2) × moles of AuCl3.

Finally, convert the moles of Cl2 to grams using the molar mass of Cl2. The molar mass of Cl2 is 2 × M(Cl). Use the formula: mass of Cl2 = moles of Cl2 × molar mass of Cl2.