Multiple Choice
How many grams of CaCl2 are formed when 15.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 gas according to the reaction: 2 Ca(OH)2(aq) + 2 Cl2(g) → Ca(OCl)2(aq) + CaCl2(s) + 2 H2O(l)?
3. Chemical Reactions
Stoichiometry
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How many grams of NaOH (molar mass = 40.0 g/mol) are there in 500 mL of a 0.175 M NaOH solution?
A
1.75 grams
B
3.50 grams
C
2.00 grams
D
7.00 grams
Verified step by step guidance1
First, understand that molarity (M) is defined as moles of solute per liter of solution. Here, you have a 0.175 M NaOH solution, which means there are 0.175 moles of NaOH in 1 liter of solution.
Next, convert the volume of the solution from milliliters to liters. Since there are 1000 milliliters in a liter, 500 mL is equivalent to 0.500 liters.
Calculate the number of moles of NaOH in 0.500 liters of the solution using the molarity. Use the formula: \( \text{moles of NaOH} = \text{molarity} \times \text{volume in liters} \).
Substitute the given values into the formula: \( \text{moles of NaOH} = 0.175 \text{ M} \times 0.500 \text{ L} \).
Finally, convert the moles of NaOH to grams using the molar mass of NaOH. Use the formula: \( \text{mass in grams} = \text{moles} \times \text{molar mass} \). Substitute the calculated moles and the given molar mass (40.0 g/mol) into this formula.
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