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Multiple Choice
Lithium and nitrogen react to produce lithium nitride according to the equation: 6Li + N2 → 2Li3N. How many moles of N2 are needed to react with 0.450 mol of lithium?
A
0.075 mol
B
0.225 mol
C
0.300 mol
D
0.150 mol
Verified step by step guidance
1
Identify the balanced chemical equation: 6Li + N2 → 2Li3N. This equation shows the stoichiometric relationship between lithium (Li) and nitrogen (N2).
Determine the mole ratio between lithium (Li) and nitrogen (N2) from the balanced equation. The coefficients indicate that 6 moles of Li react with 1 mole of N2.
Set up a proportion using the mole ratio to find the moles of N2 needed. If 6 moles of Li require 1 mole of N2, then 0.450 moles of Li will require x moles of N2.
Use the proportion: \( \frac{6 \text{ moles Li}}{1 \text{ mole N2}} = \frac{0.450 \text{ moles Li}}{x \text{ moles N2}} \). Solve for x to find the moles of N2.
Calculate the value of x by cross-multiplying and dividing: \( x = \frac{0.450 \times 1}{6} \). This will give you the moles of N2 needed to react with 0.450 moles of lithium.