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Multiple Choice
In a stoichiometric reaction, if the volume of the reaction vessel is 1.50 L and the rate of formation of Br2 is 0.020 mol/L·s, what amount of Br2 (in moles) is formed during the first 15.0 seconds of the reaction?
A
0.45 moles
B
0.60 moles
C
0.30 moles
D
0.15 moles
Verified step by step guidance
1
Identify the given values: the rate of formation of Br2 is 0.020 mol/L·s, the volume of the reaction vessel is 1.50 L, and the time duration is 15.0 seconds.
Understand that the rate of formation of Br2 is given in mol/L·s, which means it describes how many moles of Br2 are formed per liter per second.
Calculate the total change in concentration of Br2 over the given time period using the formula: \( \text{Change in concentration} = \text{Rate} \times \text{Time} \). Substitute the given values: \( 0.020 \text{ mol/L·s} \times 15.0 \text{ s} \).
Determine the total amount of Br2 formed by multiplying the change in concentration by the volume of the reaction vessel: \( \text{Amount of Br2} = \text{Change in concentration} \times \text{Volume} \). Substitute the values: \( \text{Change in concentration} \times 1.50 \text{ L} \).
Review the calculation steps to ensure that the units are consistent and the mathematical operations are correctly applied to find the amount of Br2 formed in moles.