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Multiple Choice
If you begin with 1.3109 g of iron(III) chloride hexahydrate (FeCl3·6H2O) and it is the limiting reactant, calculate the theoretical yield (in grams) of the product, Fe(C5H7O2)3, assuming complete reaction.
A
0.750 g
B
1.250 g
C
1.000 g
D
0.500 g
Verified step by step guidance
1
Determine the molar mass of iron(III) chloride hexahydrate (FeCl3·6H2O) by adding the atomic masses of Fe, Cl, and H2O. Use the periodic table to find these values: Fe = 55.85 g/mol, Cl = 35.45 g/mol, and H2O = 18.02 g/mol.
Calculate the number of moles of FeCl3·6H2O using the formula: \( \text{moles} = \frac{\text{mass}}{\text{molar mass}} \). Substitute the given mass (1.3109 g) and the molar mass calculated in the previous step.
Write the balanced chemical equation for the reaction between FeCl3·6H2O and the other reactants to form Fe(C5H7O2)3. Identify the stoichiometric coefficients for FeCl3·6H2O and Fe(C5H7O2)3.
Use the stoichiometry from the balanced equation to convert moles of FeCl3·6H2O to moles of Fe(C5H7O2)3. This involves using the mole ratio from the balanced equation.
Calculate the theoretical yield in grams of Fe(C5H7O2)3 by multiplying the moles of Fe(C5H7O2)3 by its molar mass. The molar mass can be found by adding the atomic masses of Fe, C, H, and O as needed.