Multiple Choice
What is the maximum amount of water (in grams) that can be produced when 964.91 g of C3H8 reacts with 511.39 g of oxygen according to the balanced equation: C3H8 + 5 O2 -> 3 CO2 + 4 H2O?
3. Chemical Reactions
Stoichiometry
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What volume of 0.200 M HCl solution is needed to exactly neutralize 25.0 mL of 0.150 M NaOH?
A
30.00 mL
B
37.50 mL
C
18.75 mL
D
25.00 mL
Verified step by step guidance1
Identify the balanced chemical equation for the neutralization reaction: \( \text{HCl} + \text{NaOH} \rightarrow \text{NaCl} + \text{H}_2\text{O} \). This shows a 1:1 molar ratio between HCl and NaOH.
Calculate the moles of NaOH present in the solution using the formula: \( \text{moles of NaOH} = \text{Molarity} \times \text{Volume} \). Convert the volume from mL to L by dividing by 1000.
Since the reaction is a 1:1 ratio, the moles of HCl needed will be equal to the moles of NaOH calculated in the previous step.
Use the moles of HCl and its molarity to find the volume of HCl solution required: \( \text{Volume of HCl} = \frac{\text{moles of HCl}}{\text{Molarity of HCl}} \).
Convert the volume of HCl from liters to milliliters by multiplying by 1000 to find the final volume needed for neutralization.
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