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Multiple Choice
What volume of 0.305 M AgNO₃ is required to react exactly with 155.0 mL of 0.274 M Na₂SO₄ solution? Provide your answer in decimal notation, rounded to the appropriate number of significant figures.
A
112 mL
B
556 mL
C
278 mL
D
139 mL
Verified step by step guidance
1
Identify the balanced chemical equation for the reaction between AgNO₃ and Na₂SO₄. The reaction is: 2 AgNO₃ + Na₂SO₄ → 2 NaNO₃ + Ag₂SO₄.
Determine the moles of Na₂SO₄ present in the solution. Use the formula: \( \text{moles} = \text{molarity} \times \text{volume (L)} \). Convert 155.0 mL to liters by dividing by 1000.
Calculate the moles of AgNO₃ required using the stoichiometry of the balanced equation. According to the equation, 2 moles of AgNO₃ react with 1 mole of Na₂SO₄.
Use the moles of AgNO₃ calculated to find the volume of the AgNO₃ solution needed. Use the formula: \( \text{volume (L)} = \frac{\text{moles}}{\text{molarity}} \).
Convert the volume from liters to milliliters by multiplying by 1000, and round the answer to the appropriate number of significant figures based on the given data.