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Multiple Choice
If 1.688 g of BaCl2·2H2O is mixed with an excess of Na2SO4 to form 200.0 mL of solution, what is the mass of BaSO4 that can form?
A
1.165 g
B
0.582 g
C
0.292 g
D
2.330 g
Verified step by step guidance
1
Start by determining the molar mass of BaCl2·2H2O. Calculate the molar mass by adding the atomic masses of all atoms in the formula: Ba, Cl, and H2O. Use the periodic table to find these values.
Convert the mass of BaCl2·2H2O given (1.688 g) into moles using the molar mass calculated in the previous step. Use the formula: \( \text{moles} = \frac{\text{mass}}{\text{molar mass}} \).
Write the balanced chemical equation for the reaction between BaCl2·2H2O and Na2SO4 to form BaSO4. The equation is: \( \text{BaCl}_2\cdot2\text{H}_2\text{O} + \text{Na}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + 2\text{NaCl} + 2\text{H}_2\text{O} \).
Use stoichiometry to determine the moles of BaSO4 that can form. According to the balanced equation, 1 mole of BaCl2·2H2O produces 1 mole of BaSO4. Therefore, the moles of BaCl2·2H2O calculated in step 2 will be equal to the moles of BaSO4.
Convert the moles of BaSO4 to grams using its molar mass. Calculate the molar mass of BaSO4 by adding the atomic masses of Ba, S, and O. Then use the formula: \( \text{mass} = \text{moles} \times \text{molar mass} \) to find the mass of BaSO4 that can form.