Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

6. Chemical Quantities & Aqueous Reactions

Molarity

General Chemistry

6. Chemical Quantities & Aqueous Reactions

Molarity

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Multiple Choice

What is the molarity of a solution prepared by dissolving 10.0 g of acetone, C₃H₆O, in enough water to make 125 mL of solution?

2.56 M

0.64 M

1.38 M

0.80 M

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Verified step by step guidance

First, calculate the molar mass of acetone (C₃H₆O). The molar mass is the sum of the atomic masses of all atoms in the molecule. Use the periodic table to find the atomic masses: Carbon (C) is approximately 12.01 g/mol, Hydrogen (H) is approximately 1.01 g/mol, and Oxygen (O) is approximately 16.00 g/mol. Therefore, the molar mass of acetone is calculated as:

3 \times 12.01 + 6 \times 1.01 + 16.00

g/mol.

Next, convert the mass of acetone to moles using its molar mass. The formula to convert grams to moles is:

\frac{mass}{molar mass}

. Substitute the given mass of acetone (10.0 g) and the calculated molar mass from step 1 into this formula.

Now, convert the volume of the solution from milliliters to liters, as molarity is expressed in moles per liter. Use the conversion factor:

1 L = 1000 mL

. Therefore, convert 125 mL to liters.

Calculate the molarity of the solution using the formula for molarity:

\frac{moles of solute}{liters of solution}

. Use the moles of acetone calculated in step 2 and the volume in liters from step 3.

Finally, interpret the calculated molarity value and compare it with the given options to identify the correct answer. The molarity should match one of the provided choices.