Multiple Choice
What is the molarity of a solution prepared by dissolving 10.0 g of acetone, C₃H₆O, in enough water to make 125 mL of solution?
6. Chemical Quantities & Aqueous Reactions
Molarity
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
What mass of NaOH is required to make up 100 mL of a 0.5000 M solution?
A
5.00 g
B
1.00 g
C
2.00 g
D
0.50 g
Verified step by step guidance1
Determine the molarity formula: Molarity (M) = moles of solute / liters of solution.
Convert the volume of the solution from milliliters to liters: 100 mL = 0.100 L.
Use the molarity formula to find the moles of NaOH needed: moles of NaOH = Molarity (M) × Volume (L).
Calculate the molar mass of NaOH. Sodium (Na) has a molar mass of approximately 22.99 g/mol, oxygen (O) is about 16.00 g/mol, and hydrogen (H) is about 1.01 g/mol. Add these to find the molar mass of NaOH.
Multiply the moles of NaOH by its molar mass to find the mass required: mass (g) = moles × molar mass (g/mol).
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