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Multiple Choice
What is the molarity of a 10.5% by mass glucose (C₆H₁₂O₆) solution if the density of the solution is 1.03 g/mL?
A
0.80 M
B
0.60 M
C
0.70 M
D
0.50 M
Verified step by step guidance
1
First, understand that a 10.5% by mass glucose solution means there are 10.5 grams of glucose in every 100 grams of the solution.
Calculate the mass of the solution in grams for a given volume. Since the density is 1.03 g/mL, 100 mL of the solution would weigh 103 grams.
Determine the mass of glucose in this volume. Since the solution is 10.5% glucose by mass, multiply 103 grams by 0.105 to find the mass of glucose in 100 mL of solution.
Convert the mass of glucose to moles. Use the molar mass of glucose (C₆H₁₂O₆), which is approximately 180.18 g/mol, to convert the mass of glucose to moles by dividing the mass of glucose by the molar mass.
Finally, calculate the molarity of the solution. Molarity is defined as moles of solute per liter of solution. Since you have the moles of glucose in 100 mL, convert this volume to liters (0.1 L) and divide the moles of glucose by this volume to find the molarity.