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Multiple Choice
What is the molarity of a solution made by dissolving 3.68 g of sucrose (C12H22O11) in sufficient water to form 275.0 mL of solution? (Molar mass of sucrose = 342.30 g/mol)
A
0.0039 M
B
0.013 M
C
0.134 M
D
0.039 M
Verified step by step guidance
1
First, calculate the number of moles of sucrose (C₁₂H₂₂O₁₁) using its mass and molar mass. Use the formula: . Substitute the given values: mass = 3.68 g and molar mass = 342.30 g/mol.
Perform the division to find the moles of sucrose: . This will give you the number of moles of sucrose present in the solution.
Next, convert the volume of the solution from milliliters to liters, as molarity is expressed in moles per liter. Use the conversion factor: 1 L = 1000 mL. Therefore, L.
Now, calculate the molarity of the solution using the formula: . Substitute the moles of sucrose and the volume in liters into the formula.
Finally, perform the division to find the molarity of the solution. This will give you the concentration of sucrose in the solution in moles per liter (M).