Multiple Choice
What is the molarity of a solution made by dissolving 3.68 g of sucrose (C12H22O11) in sufficient water to form 275.0 mL of solution? (Molar mass of sucrose = 342.30 g/mol)
6. Chemical Quantities & Aqueous Reactions
Molarity
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What volume of solution is prepared when 25.0 g of NaCl is added to enough water to make a 2.50 M NaCl solution?
A
0.500 L
B
0.250 L
C
1.000 L
D
0.171 L
Verified step by step guidance1
Calculate the number of moles of NaCl using its molar mass. The molar mass of NaCl is approximately 58.44 g/mol. Use the formula: \( \text{moles of NaCl} = \frac{\text{mass of NaCl (g)}}{\text{molar mass of NaCl (g/mol)}} \).
Substitute the given mass of NaCl (25.0 g) into the formula to find the moles of NaCl.
Use the molarity formula to find the volume of the solution. Molarity (M) is defined as moles of solute per liter of solution: \( M = \frac{\text{moles of solute}}{\text{volume of solution (L)}} \).
Rearrange the molarity formula to solve for the volume of the solution: \( \text{volume of solution (L)} = \frac{\text{moles of solute}}{M} \).
Substitute the calculated moles of NaCl and the given molarity (2.50 M) into the rearranged formula to find the volume of the solution.
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