Multiple Choice
What volume of solution is prepared when 25.0 g of NaCl is added to enough water to make a 2.50 M NaCl solution?
6. Chemical Quantities & Aqueous Reactions
Molarity
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You need to prepare 2.00 L of 0.100 M Na2CO3 solution. The best procedure is to weigh out:
A
10.6 g of Na2CO3
B
42.4 g of Na2CO3
C
5.3 g of Na2CO3
D
21.2 g of Na2CO3
Verified step by step guidance1
Determine the number of moles of Na2CO3 needed using the formula: \( \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \). Here, the molarity is 0.100 M and the volume is 2.00 L.
Calculate the moles of Na2CO3 required: \( \text{moles of Na2CO3} = 0.100 \text{ M} \times 2.00 \text{ L} \).
Find the molar mass of Na2CO3 by adding the atomic masses of its constituent elements: \( \text{Na} = 22.99 \text{ g/mol}, \text{C} = 12.01 \text{ g/mol}, \text{O} = 16.00 \text{ g/mol} \). The formula is \( \text{Na}_2\text{CO}_3 \).
Calculate the mass of Na2CO3 needed using the formula: \( \text{mass} = \text{moles} \times \text{molar mass} \).
Compare the calculated mass with the given options (10.6 g, 42.4 g, 5.3 g) to determine the correct amount to weigh out.
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