Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

6. Chemical Quantities & Aqueous Reactions

Solubility Rules

General Chemistry

6. Chemical Quantities & Aqueous Reactions

Solubility Rules

Previous problemNext problem

Struggling with General Chemistry?

Join thousands of students who trust us to help them ace their exams!Watch the first video

Multiple Choice

At 30.0°C, the molar solubility of barium sulfate (BaSO₄) in water is 1.20×10⁻⁵ M. Calculate the solubility in grams per liter.

2.79×10⁻³ g/L

4.56×10⁻³ g/L

1.20×10⁻⁵ g/L

5.85×10⁻³ g/L

Previous problemNext problem

Verified step by step guidance

First, understand that molar solubility refers to the number of moles of solute that can dissolve in a liter of solution to reach saturation. Here, the molar solubility of BaSO₄ is given as 1.20×10⁻⁵ M.

To convert molar solubility to solubility in grams per liter, use the formula: solubility (g/L) = molar solubility (mol/L) × molar mass (g/mol).

Calculate the molar mass of barium sulfate (BaSO₄). The molar mass is the sum of the atomic masses of barium (Ba), sulfur (S), and oxygen (O). Use the periodic table to find these values: Ba = 137.33 g/mol, S = 32.07 g/mol, O = 16.00 g/mol. Since there are four oxygen atoms, multiply the atomic mass of oxygen by four.

Add the atomic masses together to find the molar mass of BaSO₄: Molar mass = 137.33 g/mol (Ba) + 32.07 g/mol (S) + 4 × 16.00 g/mol (O).

Finally, multiply the molar solubility by the molar mass to find the solubility in grams per liter: Solubility (g/L) = 1.20×10⁻⁵ mol/L × molar mass of BaSO₄.