Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

6. Chemical Quantities & Aqueous Reactions

Solubility Rules

General Chemistry

6. Chemical Quantities & Aqueous Reactions

Solubility Rules

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Multiple Choice

How many liters of water are required to dissolve 1.00 g of silver chromate, given its solubility is 3.65×10^(-10) g/L?

1.00 × 10^10 L

2.74 × 10^9 L

5.00 × 10^9 L

3.65 × 10^8 L

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Verified step by step guidance

Understand the problem: We need to find out how many liters of water are required to dissolve 1.00 g of silver chromate, given its solubility is 3.65×10^(-10) g/L.

Identify the relationship between solubility and the amount of solute: Solubility is defined as the maximum amount of solute that can dissolve in a given amount of solvent at a specific temperature. Here, it is given as 3.65×10^(-10) g/L.

Set up the equation: Use the formula for solubility, which is Solubility (g/L) = Mass of solute (g) / Volume of solvent (L). Rearrange this to find the volume of solvent: Volume of solvent (L) = Mass of solute (g) / Solubility (g/L).

Substitute the given values into the equation: Mass of solute = 1.00 g and Solubility = 3.65×10^(-10) g/L. So, Volume of solvent (L) = 1.00 g / 3.65×10^(-10) g/L.

Calculate the volume: Perform the division to find the volume of water required to dissolve 1.00 g of silver chromate. This will give you the answer in liters.