Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
Suppose that a particle travels along the -axis and its velocity is given by for . Find the particle's displacement on
A
B
C
D
Verified step by step guidance
1
Step 1: Understand the problem. The displacement of a particle is the integral of its velocity function over the given time interval. Here, the velocity function is v(t) = 2cos(t), and the interval is [0, 5π/4].
Step 2: Write the integral for displacement. The displacement is given by the definite integral: ∫[0, 5π/4] 2cos(t) dt.
Step 3: Solve the integral. The antiderivative of 2cos(t) is 2sin(t). Use this to evaluate the definite integral: ∫[0, 5π/4] 2cos(t) dt = [2sin(t)] evaluated from t = 0 to t = 5π/4.
Step 4: Apply the limits of integration. Substitute the upper limit (t = 5π/4) and the lower limit (t = 0) into the antiderivative: 2sin(5π/4) - 2sin(0).
Step 5: Simplify the result. Use the unit circle to find sin(5π/4) and sin(0). sin(5π/4) corresponds to the sine value at 225 degrees, which is -√2/2, and sin(0) is 0. Substitute these values into the expression to find the displacement.