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Multiple Choice
A particle travels along the š„-axis and its velocity is the given graph of . Find displacement on
A
2.5
B
4.5
C
-2
D
6.5
Verified step by step guidance
1
Step 1: Understand the problem. Displacement is the integral of velocity over a given time interval. In this case, we need to calculate the integral of v(t) over the interval [0,5]. The graph of v(t) is provided, and it is a straight line decreasing from 5 at t=0 to -4 at t=5.
Step 2: Analyze the graph. The velocity graph forms a triangle above the x-axis from t=0 to t=2 and another triangle below the x-axis from t=2 to t=5. The areas of these triangles represent the contributions to displacement, with positive area above the x-axis and negative area below the x-axis.
Step 3: Calculate the area of the triangle above the x-axis (from t=0 to t=2). The base of the triangle is 2 units (from t=0 to t=2), and the height is 5 units (from v=5 to v=0). Use the formula for the area of a triangle: A = (1/2) * base * height.
Step 4: Calculate the area of the triangle below the x-axis (from t=2 to t=5). The base of the triangle is 3 units (from t=2 to t=5), and the height is 4 units (from v=0 to v=-4). Use the formula for the area of a triangle: A = (1/2) * base * height. This area will be negative because it is below the x-axis.
Step 5: Add the areas from Step 3 and Step 4 to find the total displacement. Remember to account for the sign of the area below the x-axis. The sum of these areas gives the total displacement over the interval [0,5].