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Multiple Choice
The velocity (mi/hr) of a drone flying in the air is given by v(t)=12+4t2 for 0≤t≤4 hours. Let s(0)=0. How far does the drone travel during the first hour?
A
13.3 mi
B
133.3 mi
C
8.00 mi
D
6.67 mi
Verified step by step guidance
1
Step 1: Recognize that the problem involves finding the distance traveled by the drone during the first hour. The distance traveled is the integral of the velocity function over the given time interval.
Step 2: Write the velocity function as v(t) = 12 + 4t^2. The distance traveled, s(t), can be found by integrating v(t) with respect to t over the interval [0, 1].
Step 3: Set up the definite integral for the distance: s(1) = ∫[0 to 1] (12 + 4t^2) dt.
Step 4: Break the integral into two parts for easier computation: ∫[0 to 1] 12 dt + ∫[0 to 1] 4t^2 dt. Compute each term separately. For the first term, integrate 12 with respect to t. For the second term, integrate 4t^2 with respect to t.
Step 5: Evaluate the definite integrals by substituting the limits of integration (0 and 1) into the antiderivatives. Add the results of the two integrals to find the total distance traveled during the first hour.