Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
A rock is thrown from a height of with an initial speed of /. Acceleration resulting from gravity is /. Find
A
B
C
D
Verified step by step guidance
1
Step 1: Begin by understanding the problem. The rock is thrown with an initial velocity of 25 ft/s from a height of 2 ft, and the acceleration due to gravity is -32 ft/s². We are tasked with finding the velocity function v(t).
Step 2: Recall that acceleration is the derivative of velocity with respect to time. Conversely, velocity is the integral of acceleration with respect to time. The given acceleration is a(t) = -32 ft/s².
Step 3: Integrate the acceleration function a(t) = -32 with respect to time t to find the velocity function v(t). The integral of -32 with respect to t is: ∫(-32) dt = -32t + C, where C is the constant of integration.
Step 4: Use the initial condition to solve for the constant C. The initial velocity of the rock is given as 25 ft/s when t = 0. Substitute t = 0 and v(0) = 25 into the velocity equation: v(0) = -32(0) + C = 25. Solve for C to find C = 25.
Step 5: Substitute the value of C back into the velocity equation to obtain the final velocity function: v(t) = -32t + 25.