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Multiple Choice
Heterozygous parents who have had one child with a recessive disease have a __________% chance of having a second child born with the same recessive disease.
A
12.5
B
25
C
50
D
75
Verified step by step guidance
1
Understand that a recessive disease requires two copies of the recessive allele for the disease to manifest. A heterozygous parent carries one dominant allele and one recessive allele.
Use a Punnett square to visualize the genetic combinations possible from two heterozygous parents. Each parent can pass on either the dominant allele or the recessive allele.
Set up the Punnett square with one parent's alleles on the top and the other parent's alleles on the side. The alleles are typically represented as 'A' for dominant and 'a' for recessive.
Fill in the Punnett square by combining the alleles from each parent. This will result in four possible combinations: AA, Aa, Aa, and aa.
Identify the combination that results in the recessive disease, which is 'aa'. Count the number of 'aa' combinations and calculate the probability of this occurring, which is the chance of having a child with the recessive disease.