In Exercises 21–38, letu = 2i - 5j, v = -3i + 7j, and w = -i - 6j...

Question

In Exercises 21–38, letu = 2i - 5j, v = -3i + 7j, and w = -i - 6j.Find each specified vector or scalar.||w - u||

Accepted Answer

Considering the vectors A equals 11 I minus four J and B equals negative eight I plus six J determine the following scalar. But we had the magnitude of B minus A and we have four possible answers, square root of 4 61 squared of 41 square root of 7 square roots of three. Now to solve this, let's first find vector B minus A. So vector B minus A will be the subtraction of our two vectors. We can put this in order negative eight I plus six J for vector B minus M parentheses 11 I minus four J. For start vector A, we can distribute our negative to get negative eight I plus six J minus 11 I plus four J. We can now combine our like terms. We can combine our I's by subtracting and our Js by adding, we have negative eight I minus 11 I to give us negative 19 I and we have six J plus four J to give us 10 J. Now this is our vector B minus A. We need the magnitude of the specter, the magnitude of A vector. It's just the square root of our first component A squared plus our second component B squared. Where vector is in the form A I plus B J. This means the magnitude of vector B minus A will be the square root of negative 19 squared plus 10 squared. Where we get the square root of 3 61 plus 100 or the square root of 461 we can't simplify this any further, which means our answer corresponds to answer A OK. I hope to help you solve the problem. Thank you for watching. Goodbye.

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In Exercises 21–38, letu = 2i - 5j, v = -3i + 7j, and w = -i - 6j.Find each specified vector or scalar.||w - u||

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